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Data Storage IT

How Heavy Is a Petabyte? 495

Posted by timothy
from the but-electrons-don't-weigh-anything dept.
Jon Morgan writes "Whilst heaving around numerous data storage systems to sell (they weigh A LOT!), we got to wondering: How heavy is a Petabyte of data storage? Our best guess is 365KG, which is 6 million times lighter than in 1980! But is there a lighter way to store a Petabyte?"
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How Heavy Is a Petabyte?

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  • or 2.5" drives? (Score:3, Interesting)

    by whoever57 (658626) on Wednesday July 08 2009, @06:26PM (#28629273) Journal
    I think that a 2.5 inch drive weighs less than half the weight of a 3.5 inch drive, so using twice as many of the 2.5" drives (available up to 1TB today) will reduce the weight.
  • by John Hasler (414242) on Wednesday July 08 2009, @06:33PM (#28629357) Homepage

    Whatever gave you that idea?

  • About 2 Kilos (Score:5, Interesting)

    by BBCWatcher (900486) on Wednesday July 08 2009, @06:33PM (#28629359)
    Nobody knows exactly how much data the average human brain can hold, but one estimate [geocities.com] is 500 to 1000 TB. If the average adult human brain weighs about 1.3 or 1.4 Kilos [washington.edu], then "about 2 Kilos" would hold 1 Petabyte.
  • by Chris Burke (6130) on Wednesday July 08 2009, @06:36PM (#28629393) Homepage

    Thinking about the decrease in mass of a petabyte got me thinking about Information Theory and the minimum energy required to store a bit. Or rather, to irreversibly manipulate one bit of information, which I think describes the act of writing to any kind of RAM (disk or otherwise). If I extrapolate that to also mean a mass whose rest energy is sufficient to manipulate a bit, that could give the theoretical minimum mass for a bit of storage. I don't actually know enough information theory to know that value, or even if the comparison from energy of information manipulation to mass of storage is valid, but it struck me as interesting and maybe somebody knows? What's the minimum mass of a petabyte?

  • by marcus (1916) on Wednesday July 08 2009, @06:47PM (#28629495) Journal

    and a lot bulkier than...

    a few strands of DNA.

  • by RichardJenkins (1362463) on Wednesday July 08 2009, @06:57PM (#28629609)
    Asking a question like this is about as silly as asking how wide a year is. It's just not immediately obvious that this question makes no sense because it gets confused with the similar question 'what is the lightest device(s) capable of storing a petabyte of information.
  • by clarkkent09 (1104833) * on Wednesday July 08 2009, @07:22PM (#28629841)
    Thanks for nothing Peggy LeMone. Saying that a "typical cumulus cloud" weighs as much as 100 elephants is a meaningless statement without giving us a hint as to what the hell is the size of a "typical cumulus cloud". I bet we are talking about a hell of a lot greater volume than 100 elephants.

    Here is an equally interesting piece of news for you: a pile of feathers is heavier than a tank! Of course it all depends on the size of the pile but who can bother with those little details.
  • Re:MicroSD (Score:5, Interesting)

    by Burning1 (204959) on Wednesday July 08 2009, @07:27PM (#28629895) Homepage

    Technically, if you don't count the hardware to read the data, we could simply remove the hard disk platters from the drive. Since most of the drive's weight is made up of the casing and read electronics, it would probably swing the data/weight ratio back in the favor of hard disks.

  • by W3bbo (727049) on Wednesday July 08 2009, @07:34PM (#28629949)
    No, that's diameter of the earth's orbit around the sun. A year would be the circumference which is 940 million kilometers.
  • by Anonymous Coward on Wednesday July 08 2009, @07:36PM (#28629963)

    10,886,216.9 kilograms or 10.9 kilotons is slightly less than one Hiroshima.

    So if every book in the Library Of Congress was made of TNT and you detonated them all together, the total yield would be slightly less than one very small atomic bomb. Fuck.

  • by W3bbo (727049) on Wednesday July 08 2009, @07:46PM (#28630057)
    In my head I equated orbit length to "width of the year" since I was thinking of a timeline, and a timeline has width (from 1st Jan to Dec 31st) and at each point on the timeline the earth is at a certain point on its orbit which corresponds to a distance from its initial position.
  • Re:There is a way! (Score:4, Interesting)

    by CorporateSuit (1319461) on Wednesday July 08 2009, @09:05PM (#28630873)

    Insightful? Assuming you can perfectly remember 1 byte per second, you'd be memorizing for over 100 million years. The human brain is great and all that, but no way are you going to store that much data while being able to reproduce it later.

    Considering a single "frame" of vision for a pair of human eyes is estimated at 576 megapixels (truncating at peripheral vision). We'll imagine that each pixel is assigned a 16-bit hexadecimal value. That means, each time you glance at something, each frame would be calculated at a little more than 1/1000th of a terabyte. The lowball framerate for the human eye is about 18 frames/second (things look fluid). That means that every 50 seconds, your eye is downloading a terabyte of information. He'll absorb it in less than a day through eyesight alone. That doesn't include audio, olfactory, touch, or taste. His brain's data compression will downsize a lot of that information, so it will take him more than a day, but for your i/o ports, taking in a petabyte of information is a daily task.

    You'd be hard-pressed to find a living organism that downloads information at 1B/sec

  • Re:There is a way! (Score:3, Interesting)

    by greyhueofdoubt (1159527) on Wednesday July 08 2009, @11:00PM (#28631797) Homepage Journal

    Pointless. You could put 1 billion people on a scale and have them all memorize data as fast as they could and the weight won't change (correcting for evaporation, etc.).

    -b

  • About 0.8 micrograms (Score:1, Interesting)

    by Anonymous Coward on Wednesday July 08 2009, @11:29PM (#28632005)

    Assuming you represent 1s and 0s as the presence/absence of an atom of aluminum on a sheet one atom thick, then it weighs (at the most, if you store all 1s) about 0.807 micrograms. This all fits onto a sheet of aluminum 1 atom (250 picometers) thick and about 3.35 by 1.67 centimeters in size. Though that would be some impressive hardware that could manipulate that.

  • by dido (9125) <dido@imperiuSTRAWm.ph minus berry> on Thursday July 09 2009, @12:07AM (#28632263)

    But you are converting mass into energy and energy into mass even in this case, although the amounts are ridiculously small in the case of chemical reactions, which is why conservation of mass is a more than reasonable approximation in chemistry. The mass is stored in the molecular binding energy of the battery's chemicals, and converted into the energy used when the battery discharges. For example, if you weighed very very carefully a bunch of hydrogen gas, a bunch of oxygen gas, and the water you got after combining the two (in a fuel cell reaction, which we can think of as the simplest sort of battery from a chemistry point of view), the water would weigh ever slightly less than the hydrogen and the oxygen, though the difference would be extremely small, since the binding energy difference of a water molecule versus that of hydrogen and oxygen molecules is only a few tens of electron volts, about 10^-35 kg or thereabouts, which amounts to a difference of about a quadrillionth of a gram for one mole of water. For nuclear reactions though, the binding energies we deal with are millions of times greater, and E=mc^2 is much more obvious. For instance, in the nuclear fusion of the two helium-3 nuclei to produce one helium-4 and two free protons, the helium-4 and the two protons weigh less than the original helium-3 nuclei by about 12.86 MeV/c^2, or about 6 milligrams less than if we started with a mole of helium-3 at the beginning of the fusion reaction.

A CONS is an object which cares. -- Bernie Greenberg.

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