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256GB Geometrically Encoded Paper Storage Device
Posted by
CmdrTaco
on Sun Nov 26, 2006 10:28 AM
from the passing-complicated-notes-in-class dept.
from the passing-complicated-notes-in-class dept.
jrieth50 noted that a method of using geometric shapes combined with color to store up to 256GB of data on a sheet of paper or plastic. The article says "Files such as text, images, sounds and video clips are encoded in 'rainbow format' as colored circles, triangles, squares and so on, and printed as dense graphics on paper at a density of 2.7GB per square inch. The paper can then be read through a specially developed scanner and the contents decoded into their original digital format and viewed or played."
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Robustness & Feasibility (Score:5, Interesting)
My question would be how much wear & tear can a sample of this medium stand before it is rendered unreadable? I would highly doubt one would be able to fold it--however it would be interesting to see whether creating a diagonal read/write scheme would protect from vertical & horizontal folds with the proper ECC. I think the plastic sheets could potentially be as robust as discs but would you be able to bend them? I doubt it though if they allowed it, it'd probably end up being more expensive than a disc.
Interesting technology but I'd sure like to hear a lot more of the details of how it works & how it performs before I make a solid judgment on its feasibility.
Re:Robustness & Feasibility (Score:4, Informative)
Cool... (Score:5, Funny)
Re: (Score:3, Funny)
Must be a very good scanner. (Score:3, Interesting)
Scam... (Score:5, Informative)
Re:Scam... (Score:5, Informative)
So instead of multiplying by 256, you have to multiply by 4. Result: about 140MB.
Another approach to analyzing the claim: For a given dpi resolution, how many variations of a single dot must your system be able to produce and distinguish? I get 256 GB / 302940000 dots, or 907 gradiations. Instead, we have four available.
I'm split between "scam" and "incompetent." But believing he may have actually done what he claimed is no longer an option for me.
Scam? (Score:5, Informative)
http://www.digg.com/tech_news/Scam_of_Indian_stud
Re:maybe not scam? (Score:4, Insightful)
Also, can you really have 256 distinguishable color levels on a piece of paper - especially considering that paper is not a uniform color on the micro-scale (it's made up of short strands of cellulose)?
Even if all these problems can be overcome, there is the limiting factor of diffraction, which will limit any optical system (paper or otherwise) to a data density of about 1/wavelength^2, which is roughly the density of a DVD.
C'mon Slashdot (Score:5, Informative)
It's a scam [blogspot.com].
I tried this... (Score:5, Funny)
This looks like a lie (Score:4, Insightful)
Let's see A4 - 256Gig. Let's say n different colors.
He'd need to store 256*1024*1024*1024*8 = 2199023255552 bits
on A4 = 210 mm x 297 mm = 62370 mm^2 = 2456 inch
That makes 895 367 775 bits per inch. To encode that you'd need 895 367 775 / log2(n) dots. Increasing the number of colors can buy you some leeway, but not that much.
The surface area of such a dot would be 1/30 000 000 th of a millimeter.
Where will you find paper that has surface flaws significantly smaller than that ? No matter what the encoding, you're still going to need it. So this is a scam, plain and simple.
Re:This is a lie (Score:4, Informative)
256*1024*1024*1024*8*(10/8) = 2.749 * 10^12 [allowing for 25% extra - error detection/correction]
Now, the area of a sheet of paper in mm^2:
210 mm * 297 mm = 6.237 * 10^4
Let's make an assumption: it would be tough for a scanner to correctly identify more than 256 colors (blues especially are problematic). So, going by a pixel based method, we can store 8 bits per pixel, so the number of pixels needed is:
2.749 * 10^12 / 8 = 3.436 * 10^11
Pixels per mm^2 will therefore be:
3.436 * 10^11 / 6.237 * 10^4 = 5.509 * 10^6
Taking the square root of this figure and inverting will give us the size of one side of a pixel in mm, so:
1 / (5.509 * 10^6)^.5 = 4.260 * 10^-4 mm =
This is smaller than the wavelengths of some frequencies of visible light, therefore a large portion of the spectrum is gone in terms of colors that can be used. Eliminate these colors and you increase density yet again, requiring you eliminate more colours. By the time you get to monochromatic (black white), which you will, the size is smaller than the wavelength of ANY visible light.
So, for this storage density, either you are scanning in ultraviolet light (and printing using an appropriate ink) to get a small enough wavelength, or you have thrown out light all together and you are using an electron microscope as your scanner. (Note - ever see electron microscope images in color? Can't exist unless colorized).
Fairly clever hoax though - if they had stuck with, say, 16GB then it would not have edged into the impossible.
Re:RTFA (Score:5, Informative)
Bzzt.
Encoding data using dots is the most efficient method possible. He has to print the image somehow, and scan it back in again. No combination of triangles and circles can circumvent the resolution limit, which is what is being calculated here.
By showing that the claim exceeds all practical limits of optical resolution (and probably the absolute physical limits), we show that what we have is just another magical compression scam.
He says that he's "doing something differently"; we've proved that what he claims to be doing is impossible. End of story.
Re:RTFA (Score:5, Informative)
Bzzt.
Encoding data using dots is the most efficient method possible. He has to print the image somehow, and scan it back in again. No combination of triangles and circles can circumvent the resolution limit, which is what is being calculated here.
By showing that the claim exceeds all practical limits of optical resolution (and probably the absolute physical limits), we show that what we have is just another magical compression scam.
He says that he's "doing something differently"; we've proved that what he claims to be doing is impossible. End of story.
Assumptions (none of them unreasonable, all of them quite generous even):
1440dpi
8 bit color
8" x 10.5" printing area
Even assuming perfect readability, this resolution yields only 1.4GB per page. Talk of "shapes" is smoke and mirrors to obfuscate one of the cold hard facts of information theory: you cannot accurately represent all permutations of 8 bits of information if you've budgeted less than 8 bits. Compression schemes allow you to compress repetitive patterns is you know they're going to be there beforehand (e.g. an almost arbitrarily large number of only 1's or only 0's can be represented with run length encoding), but X bits of random data requires X bits of allocated space.
Re:This looks like a lie (Score:5, Insightful)
Let's say that we're drawing very tiny triangles as close to our resolution limit as possible (which we must do if we want to fit a lot of them). Such a triangle might be, say, 3 x 3 resolution units, so a hollow, up-triangle might look like this:But look: there are 2^9 (or 512) possible shapes that can be made in this grid -- so by using only 64 different triangles, we are actually underutilising our medium. It doesn't matter what technology you use, any shape other than a "dot" is itself made out of smaller units like "dots", so restricting our vocabulary to certain shapes (rather than arbitrary sequences of dots) will waste space.
Bullshit, complete bullshit (Score:5, Informative)
Do The Numbers (Score:5, Insightful)
Alright, that's 21.6 gigabits per square inch.
For the sake of argument, let's say that the printer and scanner can reliably print and scan colour at 24-bit fidelity (which is nonsense, but makes the numbers nice and tidy): 900 million pixels per square inch.
That's 30,000 dpi.
That means you'd have to print and scan pixels less than a micron across. In full colour.
I don't think so.
hmmm... (Score:5, Interesting)
Ultimate compression? (Score:5, Insightful)
Lets just imagine for one second that its true.
Instead of printing this data onto paper, why not just store it loslessly in a bitmap file? After all, printers only have a certain DPI and a certain amount of colours. If you could take this bitmap file and somehow extract 256GB of data from it, that sure would be some cool magic.
I find the comments amusing. (Score:5, Funny)
I wouldn't be so quick to say this is a scam.
I've always defended Slashdot, but.. (Score:5, Insightful)
It's time for some sort of shakeup with editorial at Slashdot. Digg is imperfect and a lot of the users are idiots (I'd certainly say the average Slashdotter is significantly more intelligent and clued-up) but Slashdot is slow and has a poor editorial process. Could we, perhaps, strive to produce something with the perfect mix of the two? Fast news, the ability to vote, etc, but coupled with the superb Slashdot audience? It's all false hope, I'm sure, but I have more hope in people than technology.. so Slashdot is just the place to bring this up IMHO.
Re:Not Dots (Score:4, Informative)
An upper bound (Score:5, Informative)
Here's an upper bound as a check on your numbers (not restricting ourselves to a small dictionary of shapes). I'll give away the punchline: My numbers agree with yours, but 256 GB is not possible using printers and paper.
Assumptions: I use your printer linear resolution of 1200 dpi, and assume that adjacent pixels can be resolved at this resolution. I also assume that 256 different colors can be distinguished, as you do, and that the paper we are using has an area of 96.6763 inches^2, also as you do.
Calculation: With a linear resolution of 1200 dpi, one can fit 1440000 dots per square inch (Check!), and so 139213872 dots on a sheet of A4. With 256 colors we can store a number as large as (number_of_colors)^(number_of_dots). So:
256^139213872 = 2^N (where N is the equivalent number of bits)
(2^8)^(139213872) = 2^N (recognizing that 256 = 2^8)
2^(8*139213872) = 2^N
N = 8*139213872 (bits)
(and if we just divide by 8 again to get bytes...) => 139213872 bytes = 139 MB
Discussion: This theoretical upper bound is three orders of magnitude smaller than what is being claimed by the article: It is not possible to store 256 GB on a sheet of A4. My result does however agree with your result in that the inequality (my_result)>(your_result) holds, as it should. Ad it's really not too shabby: Accounting for 8-to-14 conversion for some error correction, we can store slightly under 80 MB in this way.
Different assumptions: If I instead use your 2000 dpi laser printer figure, then I can fit 4000000 dots per square inch, and so 386705200 dots on a sheet of A4 and so almost 386 MB. (Including error correction, one might store 220 MB.) Pretty impressive!
The Absurd: Right now, many modern semiconductor fabs have working 90 nm photolithographic processes. That means that the smallest feature size is 3.54330709×10^(-6) in, and the linear resolution is about 282222 dpi. If all we print is the first metal layer, then a dot can either be "with metal" or "without metal" -- that is, one bit. And on a silicon wafer with an area the same as that of a sheet of A4 paper, we can then fit 7700207603555 dots, or 962 GB. Hard drives are about halfway there!
Re:This is brilliant (Score:5, Funny)
We truly live in the golden age of technology.